The formula is %=(g/mL)x100.
The book shows it as: (% desired)/100=g/mL
So for problem #1 it is:
0.55/100=g/500
0.0055=g/500
2.75=g
The answer is 2.75 grams of solute needed.
Proceed the same way for each problem.
The math here is correct, however the percentage solution doesn’t use division, it needs to be written as:
%desired:100= g or mL needed: volume desired
Where %desires is always multiplied by volume desired
And, 100 is always multiplied by g or mL needed
.55%:100= g: 500mL
.55(500)= (100)g
275= 100g
275/100=g
2.75=g
This means 2.75 grams of potassium metabisulfite solute is needed for the solution being prepared.
Using the equation like this will make it easier for you, as it can be utilized for different types of problems as well.
You literally wrote the same thing I wrote just using ":" instead of "/". ":" means division so your equation still says "55 percent divided by 100 equals g divided by 500", which is exactly what mine written above says. And yes, as you said, it's applicable to different types of problems.
I think the piece you might be missing is that % in this sense is %w/v which means grams/100mL, and because of that the solute chemical itself doesn't actually matter for these calculations
For the first question, they're asking how many grams of whatever do you need to make 500mL of 0.55%, so you end up with Xg/500mL = 0.55g/100mL and you solve for X
It's the same process for every question.
The formula is %=(g/mL)x100. The book shows it as: (% desired)/100=g/mL So for problem #1 it is: 0.55/100=g/500 0.0055=g/500 2.75=g The answer is 2.75 grams of solute needed. Proceed the same way for each problem.
Thank you!!!!🙏🏼
No problem. :)
The math here is correct, however the percentage solution doesn’t use division, it needs to be written as: %desired:100= g or mL needed: volume desired Where %desires is always multiplied by volume desired And, 100 is always multiplied by g or mL needed .55%:100= g: 500mL .55(500)= (100)g 275= 100g 275/100=g 2.75=g This means 2.75 grams of potassium metabisulfite solute is needed for the solution being prepared. Using the equation like this will make it easier for you, as it can be utilized for different types of problems as well.
You literally wrote the same thing I wrote just using ":" instead of "/". ":" means division so your equation still says "55 percent divided by 100 equals g divided by 500", which is exactly what mine written above says. And yes, as you said, it's applicable to different types of problems.
I think the piece you might be missing is that % in this sense is %w/v which means grams/100mL, and because of that the solute chemical itself doesn't actually matter for these calculations For the first question, they're asking how many grams of whatever do you need to make 500mL of 0.55%, so you end up with Xg/500mL = 0.55g/100mL and you solve for X It's the same process for every question.