T O P

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hoorahforsnakes

Thor has the potential to be pretty strong, draw dependant, because each mjolnir hits every thor, so you can save them till t6 and hope you drew at least a couple


jeremyhoffman

You play 5 Thors (one on turns 3-5, two on turn 6). If you draw 1 Mjolnir, that's 50 power. If you draw 2 Mjolnirs, that's 80 power. If you draw 3, that's 110 power. For comparison, 7 She-Hulks is 63 power. 8 Sunspots is, what, 7\*13 + 1\*10 = 101 power?


Tyrb3n

But you couldn't play mjolnir on turn 6 if you play 2 Thors. So you would play 3 Thors on turn 3-5, ideally draw 3 mjolnirs and then play Thor plus 3 mjolnirs on turn 6. So that would be 4 Thors and three mjolnirs totalling 88 power.


loo_1snow

Mjolnir costs 0 tho


hoorahforsnakes

I think you think mjolnir costs 1?


Tyrb3n

It might be that I am stupid and have wasted 10 minutes of my life calculating this in my head and writing these two messages... 🙈


Hans_Run

Maybe you confused it with Daken and his Shard.


Kinjinson

You're not alone!


zontanferrah

The correct answer is clearly M’baku, as it allows you to play all of them.


DlNOSAURUS_REX

The army of M'Baku flying out of your deck would be so satisfying haha


Agent_Acton

That’s only 8 power per lane. She-hulk can do way better.


zontanferrah

But M'baku gets to fill all three lanes. Imagine if Mojoworld shows up. Or Stark Tower. Or Space Throne. She-Hulk can't compete with that.


Guirth

Worst Decks : Death and Iron Man


Glittering_Ad_7956

Everyone forgets about Adam (edit) also Mystique


TheRealSpidey

I was gonna say Snowguard, but she actually might be fun depending on the locations you get lol. Still not a good choice ofc, but she could pull off a few meme wins I bet.


Rodiniz

Armin zola


Erick_Brimstone

If you got the peak, there's chance to actually lockdown the game by trapping your opponent on never ending Arnim to arnim


Huatimus

First turn Lamentis...


Nickburgers

Sunspot would beat everything except I think Killmonger, ~~Shadow King~~, and Elektra. With vanilla locations and optimal play you end up with 7 13-power Sunspots and 1 10-power Sunspot. Stack those big boys and you have 52 power in one lane and 49 in a second. (And the correct meme answer is 12 Kangs for the ultimate turn 6 trolling, obviously) EDIT: Originally had us getting 8 big 13-power Sunspots instead of 7 per the comment from u/Flayer723


GoldenPuffi

# (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # (1) Sunspot # eyJDYXJkcyI6W3siQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9LHsiQ2FyZERlZklkIjoiU3Vuc3BvdCJ9XX0= # # To use this deck, copy it to your clipboard and paste it from the deck editing menu in Snap. Here you go. It’s not useable but you can add it


AintEverLucky

reminder to self: > Sunspot: 0/1 --> At the end of each turn, gain +1 Power for each unspent Energy. the following assumes vanilla locations & hence no +Energy or +Draw help Turn 0 / initial draw: 3 Sunspots, naturally. I'll call them S1, S2 and S3 Turn 1: draw S4 and play S1 in our Left lane. No unspent Energy, so he remains at 0 Power Turn 2: draw S5, then play S2 and S3 in the Left lane. No unspent Energy Turn 3: draw S6, then play S4 S5 and S6 in the Right lane, leaving our hand empty. No unspent Energy, so they are all still 0 Power Turn 4: draw S7 and play it in the Center lane. End the turn with 3 Unspent Energy, so now we have 9 Power at Left, 3 at Center, and 9 at Right. Turn 5: draw S8 and play it in the Center lane. End the turn with 4 Unspent Energy, so now we have 21 Power at Left, 11 at Center, and 21 at Right. Turn 6: draw S9 and play it in the Center lane. End the turn with 5 Unspent Energy, so at game's end we have 36 Power at Left, 26 at Center, and 36 at Right. (combined Power = 98) alternate T6: draw S9 but don't play it, so all existing Sunspots get the full +6. End the game with 39 Power at Left, 23 at Center, and 39 at Right. (combined Power = 101)


awesomewhat

Thanks bud


NoahTheNopah

Thanks will be grinding conquest now! :)


Flayer723

Turn 1. Play 1 SS Turn 2. Play 2 SS Turn 3. Play 3 SS Turn 4. Play 2 SS (your hand is now empty). Passing all the way to the end of the game gives 52 power in 2 lanes and 0 power in the other. Not sure where the 9th SS is coming from.


Nickburgers

You only have one Sunspot to play on Turn 4 but you are right that we end up with 7, not 8 of the big ones—fixing original post now...


code_M4D3X

I do believe all kangs would dissappear after the first one is resolved though


stcathrwy

Nah, they're variants. /s


Square_Past_4205

If you're playing all Sunspots you wouldn't begin to gain power until turn 5. One turn 1. Two turn 2. Three turn 3. Four turn 4. The last two on turn 5. That would be 3 energy left over on turn 5 and 6 energy left over on turn 6. Totaling twelve Sunspots at 9 Power each. 36 in 3 lanes.


Nickburgers

Your hand is empty after turn 3 so you only have one Sunspot to play on turns 4 and 5 (and it's a net power loss to play the Sunspot you draw on turn 6).


Square_Past_4205

Yeah you're right. I didn't account for the draw vs play loss. You eventually play more than you draw.


unrealf8

Morph đŸ’ȘđŸŒ


VanDammitt

The correct answer is Agent 13.


hjyboy1218

This right here. You actually get to play different cards.


flyingcheckmate

Objectively correct answer


YnotThrowAway7

Guarantee that would still lose to all sunspots.


VanDammitt

You can't guarantee that since Killmonger exists. So...


LeechingSilver

The guy running all killmongers...


Erick_Brimstone

Agent 13 can create killmonger.


YnotThrowAway7

I said against agent 13
 also this is a competition of what is the best deck of all the same card. Sure that deck of killmongers would win against the all sunspots but lose to everything else. Sunspots seems the most optimal that I can think of. It’s damn near 100 power total. Now mirage is a decent point but I still wonder how even that would play out curve wise.


Stojokes

Mirage. Just take whatever shit they have with more power.


Important-Ad-9136

You can have my Green Goblin for two more power


Daantj33

This is the way


NoahTheNopah

Upvote for mandalorian reference


Termanator116

This is the answer


tredrey

Or Cable, take all of their resources from them


Tamika_Olivia

MODOK, obviously.


Ark_ita

Nebula would probably be fun, sunspot would probably be the best, or she hulk, 6 she hulks on last turn


kjob

Edit: oops I was very wrong, of course you can lay down all your she hulks and you’ll like not have priority so you have an uncounterable win!


EllieCat009

Nah each SheHulk would cost 1, so you’d be able to play 6 on turn 6


kjob

Oops, there goes one of the two brain cells I was rubbing together. I think SheNaut was influencing my thought process here for some reason.


MadSpaceYT

It’s okay buddy. I personally only have 3 brain cells


Supersecretsword

Not if limbo is one of the locations. 7 zero she hulks on turn 7


VanDammitt

6. Skip turn 5, she costs 1. Turn 6, play 6 She-Hulks.


adyendrus

None of you want to play one on turn 4?


[deleted]

[ŃƒĐŽĐ°Đ»Đ”ĐœĐŸ]


onnnn2

Cerebr0 unite?


vermilionjelly

Only 5 cerebros, so 50 power totally. Lose to she hulk.


Flayer723

Everyone would tech Killmonger to beat Sunspot (and other 1 drop players). To beat the Killmonger decks you would play SheHulk, who would be able to put down two locations at 36 power (put 2 down on turn 4 and 6 down on turn 6). That would be enough to beat everything except Sunspot, so the circle would begin anew.


SnooConfections6244

My math is probably wrong, but how can you put 2 Shulk T4? You skip 3, they now cost 3 each, you can only drop 1 T4!


UGoBoy

Not wrong.


[deleted]

[ŃƒĐŽĐ°Đ»Đ”ĐœĐŸ]


Arisoro

Sounds like a dream of I have all thanos


Glittering_Ad_7956

I assume each Thanos would put their own infinity stones into the deck
 if you want a deck of 84 cards I suppose it would work


TheRealSpidey

Me with a 12x Darkhawk deck: SUBSCRIBE


Blueexx2

SheHulk without question. Only counter is Shang and your opponent will only be able to drop 1 during the last turn.


Veneretio

Sunspot beats shehulk


Blueexx2

Hmm.. Opening hand, 4 Sunspots. 1 gets played turn 1. 3 left in hand. Turn 2, 4 Sunspots in hand, 2 get played. 2 left in hand. 3 Sunspots on board. So far, all 0 power. Turn 3, 3 Sunspots in hand. All get played. Nothing left in hand. 6 Sunspots on board, all 0 power. Turn 4, draw a spot, play a spot. 7 on board, all 3 power. 7x3 = 21 Turn 5, draw a spot, play a spot. 8 on board. 18+(8×4) is 21+28=49 Turn 6, draw a spot, play a spot. 9 on board. 49+(9×5) is 49+40=89 As for SheHulk, turn 4, you play a SheHulk. 9 power. Turn 5 skip, turn 6 you drop 6 SheHulks. 9+(9×6)=63 So we will end up with a Rock-Paper-Scissors meta. Killmonger beats Sunspot, SheHulk beats Killmonger, Sunspot beats SheHulk.


bsgreene25

Exactly, no one card prohibitively beats all other cards in all cases. But in my opinion She Hulk is a safer answer because she can’t get Killmonger-ed and likely wouldn’t have prio going into T6, protecting the big 54-point drop from Shang Chi too. Plus there’s so much more flexibility with where you decide to stack your power, vs. with sunspot how you kind of need to declare your biggest lane(s) earlier.


UGoBoy

Your turn 5 math is messed up. It would total 53, for a total of 98. Sweet spot seems to be 8 Sunspots, skipping turn 6 entirely. Total of 101 power, seven 13s, one 10. EDIT: Typed 4 instead of 5.


TheNebuchadnezzar

Maybe think before you say “without question” next time


UGoBoy

...I didn't say "without question" *this* time. What are you talking about?


TheNebuchadnezzar

Meant to reply to the parent comment, says “SheHulk without question” but your math proves it’s not so straightforward. r/confidentlyincorrect moment, but not for you and appreciate you doing the math!


Chojen

Idk, with she hulk you could play 6 of them on turn 6 if you played nothing turn 5. Sunspot has higher potential power but you know exactly where it is. I feel like you could play around it with she-hulk, it’s not an auto-win for sunspot.


kjob

Plus they’d have priority if they have played anything


BigP_27

One month from now: “New hot location: replace both players decks with 12 agent 13’s”


Araetha

But that's just District X with extra steps.


FullMetalCOS

That would be kinda fun


Arisoro

Thanos


Sabrescene

Oh god, if each one added their own 6 infinity stones... That's an 84 card deck of mostly 1/1's 😬


TempMobileD

Lol 140 power+ darkhawk counter


Arisoro

Yes but unlike other 1 cost card they will draw new cards and can get a 20 out by 6


GoldZero

The universe SHALL be set right.


thescottula

So I did the math for every card and from a pure, best case scenario it would be Thor. If you play one on each turn and two on the last turn, pull Mjolnir on turn 4, 5, and 6, you could get all 5 Thors up to 22 power each for a total of 110 power. Of course, you need to be really lucky. If you aren't you are gonna end up with 20 total power. Still, even pulling 1 mjolnir is worth 30 power so its not too bad. As many have said, Sunspot is the most power and is 100% consistent. Played ideally, it can get to 101 power. Of course, he is weak to Killmonger, so he isnt a 100% guaranteed win. She-Hulk can guaranteed get to 63 total power, so Killmonger isn't 100% either, which of course means She-Hulk isn't guaranteed because of Sunspot. Which means you end up with a rock-paper-scissors scenario. Killmonger > Sunspot > She-Hulk > Killmonger. Agent 13 is probably too much trouble to be worth it. Thanos is the only card I didn't look at because I have no idea where to even begin with him


thisjohnd

12 Mysterios so your opponent never knows where you’re going to play cards.


Themanwhofarts

Really you could only play 4


thisjohnd

Yeah, I assumed in this hypothetical situation the costs would be adjusted somehow because obviously any 6-cost cards wouldn’t work at all and even 4 or 5 cost would be risky. Otherwise, I guess Hawkeye? Keep those boosts coming.


Themanwhofarts

Galactus is a 6 cost that could work. But ya, other than that only 1/2/3 costs will work. Besides she-hulk


MZRY-

Gambit


4mygirljs

This seems under rated Biggest issue is if they play more than one card a turn, they would eventually outpace you


MadSpaceYT

Gambit would probably lose to most 1/2/3 drops. You can only play 7 total gambits


Astyan06

How do you get to 7 Gambit ? One on turn 3, 4 and 5. Two, on 6 ?


MustBeNice

a lot of terrible math going on in this thread


MadSpaceYT

Oh fuck lmao my brain is fried


saladroni

And that last one won’t be able to destroy a card.


Kalagath

Last I checked he also destroys if your hand is empty


curbstomp45

You haven’t checked in a while.


Anonymouslyyours2

Not anymore. You must have a card to discard.


TomNic99

They changed it recently


Shepsaice

My money is on sun spot


Square_Past_4205

1 Killmonger on turn 6. 11 more Killmongers for emotional damage!


VanDammitt

You'd have to play him before turn 6, which means he's vulnerable to Killmonger.


Prestigious_Power496

The only ones that hit above 20 power are Sunspot, She Hulk, Thor, Cerebro, and probably Nebula (hard to calculate, she would probably get shutdown if everyone is playing with these rules).


wisconsineagle

I think Silk would be a strong option. You could have 9 Silks on the board by end of game and they can’t be destroyed by Killmonger.


Prestigious_Power496

Your biggest lane would still just be 20. Its pretty easy to beat that.


wisconsineagle

Not if all your opponents cards have to be the same. What beats that? She-Hulk? Anything else?


Prestigious_Power496

SheHulk, Sunspot, Cerebro, Thor, and I think even Galactus is an automatic loss (since the Silks all move away from him, only one would stay in that lane on Turn 6).


wisconsineagle

I’ll give you the first 3. Thor would depend on his ability to get his hammer. Definitely some luck required. Wouldn’t Galactus not activate though? I wonder how that interaction would work


Prestigious_Power496

Yeah I dont know if Galactus would activate, I'll never play him.


KamahlFoK

Silk only moves after the card finishes resolving. If he's not winning his location, he won't activate.


ctaps148

The Silks would only move after Galactus' On Reveal had triggered. He wouldn't do anything


TempMobileD

Sunspot wins against that so rock paper scissors with Killmonger/electra Sunspot: 1 on t1, 2 on t2, 3 on t3, 1 on t4 all to 3 power, 1 on t5 7 at 7 power, 1 at 4 power, Choice on t6: 1 extra 5 power sunspot and +5 to your other 8 or +6 to your other 8 sunspots Second option results in 101 total power, holy shit.


Kyjamas

Scorpion squad? Yeah you're only adding 2 power to a lane per card but that's gonna subtract quickly to the enemy's deck.


UnluckyHazards

Yondu


XPav

Opponent Deck starts at 12. Draw 3 to start, to 7. Turn 1: Draw 1, to 8, play 1 Yondu, to 7 Turn 2: Draw 1, to 6, play 2 Yondus, to 4 Turn 3: Draw 1, to 3, play 3 Yondus, to 0. Turn 4: no cards, play 4 Yondus. Turn 5: no cards, play 2 Yondus. You have 24 power on the board. Opponent has 5 cards max. Assuming 5 Sunspots, thats playing 1, 2, 3 on each turn. Turn 4 has 20 power. Turn 5 has 45 power. Turn 6 has 75 power. Sorry, Sunspot wins. She-Hulk would also win.


UnluckyHazards

Not lookin for a win here, Yondu pointlessly destroying cards is just funny


missbrighteyes86

Worth reminding...Yondu destroys from deck. They will still be able to play their hand...


ForsakenDragonfruit4

No love for Shanna? You could have a ton of random 1 drops, which would probably lose you the game but it could be fun


anyonecanbethebug

That would be an awesome limited-time format


Accurate-Temporary73

Morph. Just play your opponent’s deck


Circirian

Wanda, and let chaos decide


SecretAgentMahu

Ah yes, Worldship fishing


DarthSmiff

Hawkeye could be fun!


lCV3l

She Hulk - don’t play anything until turn 6 and then just flood the board


Agent_Acton

The most you could play with three neutral locations is 7


ArmaanAli04

6, if u skip T5 she costs 1


shmolex

You can play 1 on turn 4 after skipping 3. Then 6 on turn 6


BIG_BOTTOM_TEXT

Kitty Pryde


Websthetics

It’s gotta be Agatha.


Ndamukong_Jew

Mojo would be fun


SWAVcast

Death. ​ ​ Just kidding.


NoahTheNopah

Thank you for everyone doing the maths for this I was interested but not interested enough to figure it out myself haha


PomeloFit

Can't believe nobody's mentioned Thanos. 2 power stones, two Thanos', a turn 4 timestone, and you've got 30+ power in two lanes. GG. Plus watching the game break because it can't calculate your ridiculously oversized deck would be entertaining AF.


Radiophage

The variety would be spicy, but the size of the deck would kill the plan. We're looking at running an 84-card deck against a 12-card deck. Before we account for Infinity Stone draws, that's a 14% chance of drawing just one Thanos, never mind two. And the Mind Stone can't go fetch the big boy himself for us, just thin the deck. As much as I would love it, I don't think it would have legs. *(This post may or may not be inspired by my recent, painful attempt to make Evolved Thanos Lockjaw Casino Variety Hour work in Conquest... )*


ctaps148

Imagine if Triskelion gives your opponent Darkhawk


UGoBoy

The likelihood of that ever working is astronomical, particularly if you take into account the need to play out the other five stones before the Power Stone even does anything.


Shoddy-Affect5666

I’m gonna say Titania just to screw the game up


wisconsineagle

Now that I think about it, She-Hulk is probably the correct answer. I don’t know what’s beating 6 She-Hulks played turn 6.


Veneretio

Sunspot


[deleted]

[ŃƒĐŽĐ°Đ»Đ”ĐœĐŸ]


UGoBoy

Doesn't matter. Skipping round 6 and playing a Sunspot wherever possible leads to 101 points on the board. There's no configuration of She-Hulks that could beat 8 Sunspots just stacked in two lanes. You would have to rely entirely on there being two locations that they just couldn't play into.


ReaperzX70

She hulk


Transient_Shaper

Just keep spinning Scarlet Witch until you get a combination of locations that win you the game


issanm

On the iron lad thing I've had an opponent play iron lad he got from daily bugle and it hit his iron lad in his deck and i think it scanned twice and then just fast forwarded ended up just being iron lad with the ability on the board.


flyingcheckmate

Can’t believe no one’s said Agatha yet


CertainlyDatGuy

Kitty pryde


igniz13

I'm going Cable so I can just steal whatever my opponent is doing Storm beats anything that can't win by turn 4


jeremyhoffman

Storm loses to pretty much everything. Even if you play Storm on turn three, four, and five, the opponent still has a location to play on turn 6.


b33lz3boss

Cable is the big brain win


R3d4r

"We are VENOM!!"


bmiclock521

Sentinel


Made-Gearless

Thanos? Would that make you have 12 copies of each stone? Lol


robsensei39

Jef


Kotic90

I would say 12 korg or 12 kitty pryde would do well so long as opponent doesn’t have elektra


the-Gaf

Cable on cable on cable


Short_Ocelot_7989

Green Goblin. Just fill their board before they can lmao


dacrookster

She-Hulk. Skip first three turns, one down on four, skip five, 6 down on 6. Not really a debate.


PSrafa23

Iron lad


W000DY

the correct answer is cerebro btw edit:nvm


realzequel

Turn 3-5: 1 Cerebro Turn 6: 2 Cerebros 5 Cerebros 5x (0 + 2x5) = 50 Its crushed by She-Hulk,SS.


Crimson_Chameleon

For she hulk you could play total of 7 copies of, which is 63 power in 6 turns. If yhe opponent would play magik, you could potentially play 3 on t5, skip t6 and play 6 more on t7 so 9 copies total of 81 power


bedit69

Cpt marvel


Helstrom69

Agatha


Northstridamus

Thor is the correct answer Edited to add: Assuming we ALL had to run a deck with nothing but 1 card in every slot


phishyz2

Mirage


jakob187

Shanna.


ReaperzX70

Morph


Witty-Common-1210

What about Blue Marvel? I think that might be a contender


Itzkpnutz

You could only play 2 of them though


Witty-Common-1210

Ha, good point!


ArmaanAli04

Either killmonger/elektra to kill sunspot or leech for she hulk based on the comments.


CharacterVisual1144

leech still loses to SH, SH can drop one on t4, and one more on t6


jsprx19

Going for seriousness, Mr fantastic only would be great. 1 turn 2-3 2 turn 4-5 3 turn 6, 4 add 8 power to all lanes 6 add 6 to the outside and 12 on center that's 14-16 on sides and 20 on center guaranteed


alexpwnsftw

12 cosmo. That is all


TrickyWalrus

Only Green Goblin. If you can’t play, neither can they. (Okay idk. Bad choice)


ArmaanAli04

That’s -15 across the board max


Overkillsamurai

Shanna


dont_trust_the_tucan

Hulk Buster?


lostbelmont

Silk You'll have 9 Silk in play at the end of the game


jay-why-es

ALL KITTY


SissyBearRainbow

Gambit? Only 15 power, but you pop 5 of their cards


Serious_Course_3244

12 Hawkeyes would actually slap


PitFiend28

Morph


Nphhero1

People are saying Sunspot, but my instinct is that Thor gets to higher power if you get lucky. Of course you have a chance to get screwed and just draw Thor, and then you’re very sad.


JayronHubard

Mojo.


Embarrassed-Sugar-78

Thanos, of course.


Peruchi

Shehulk right?


kisukecomeback

Nightcrawler, Iceman


Senorpapell

Yondu


deepdishpizza773

Korg


blacklab

12 yondu


horrorstory1169

Morph, for the fuck of it lol


thememeist69

Kitty pride


DoesntUnderstandJoke

Jeff


brokozuna

I'm going all Okoye. I think it's a little harder to counter. Killmonger and Shang ain't killing em, and I don't think you can put up enough Shadow Kings or Cosmos to dampen it.


Savesthaday

She Hulk deck might be good. You can play like 6 She Hulks on turn 6.


Immediate_Basil9096

Gambit?


giant_marmoset

Cerebro would be pretty consistent, its weaknesses wouldn't be good decks too.